冀北数据总览添加导出功能
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@@ -54,6 +54,9 @@
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:value="item"></el-option>
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</el-select>
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</el-form-item>
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<el-form-item label="关键字筛选:">
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<el-input v-model="tableStore.table.params.searchValue" clearable placeholder="请输入关键字"></el-input>
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</el-form-item>
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</template>
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<template #operation>
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<el-button type="primary" icon="el-icon-Tickets" @click="makeUp" v-if="!VITE_FLAG">补招</el-button>
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@@ -285,7 +288,7 @@ const tableStore = new TableStore({
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// tableStore.table.params.searchEndTime = tableHeaderRef.value.datePickerRef.timeValue[1]
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},
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loadCallback: () => {
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tableStore.table.data = tree2List(tableStore.table.data, Math.random() * 1000)
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tableStore.table.data = tree2List(filterTreeByKeyword( tableStore.table.data,tableStore.table.params.searchValue), Math.random() * 1000)
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tableStore.table.column[0].title = formData.value.statisticalType.name
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chartsRef.value && chartsRef.value.getTableStoreParams(tableStore.table.params)
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@@ -305,6 +308,7 @@ const tableStore = new TableStore({
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tableStore.table.params.deptIndex = ''
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tableStore.table.params.filterName = ''
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tableStore.table.params.searchValue = ''
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tableStore.table.params.statisticalType = []
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tableStore.table.params.scale = []
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tableStore.table.params.manufacturer = []
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@@ -339,6 +343,78 @@ const tree2List = (list: any, id?: string) => {
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return arr
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}
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/**
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* 树形结构按名称筛选:保留匹配节点+所有上级+所有下级,保持原树形层级
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* @param {Array} treeData - 原始嵌套树形数据(根节点数组)
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* @param {string} keyword - 筛选关键词(name包含该关键词即匹配)
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* @returns {Array} 筛选后的嵌套树形数据,保持原层级
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*/
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function filterTreeByKeyword(treeData, keyword) {
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// 关键词为空,直接返回原树(深拷贝,避免修改原数据)
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if (!keyword || keyword.trim() === '') {
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return JSON.parse(JSON.stringify(treeData));
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}
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const targetKey = keyword.trim();
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// 存储需要保留的节点ID(匹配节点+所有上级+所有下级)
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const keepIdSet = new Set();
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// 第一步:递归遍历树形,标记所有需要保留的节点ID
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const markKeepNodes = (node, parentNodes = []) => {
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// 1. 若当前节点名称包含关键词,标记自身+所有上级+所有下级
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const isMatch = node.name && node.name.includes(targetKey);
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if (isMatch) {
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// 标记自身
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keepIdSet.add(node.id);
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// 标记所有上级父节点
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parentNodes.forEach(pNode => keepIdSet.add(pNode.id));
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// 标记所有下级子节点(递归)
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const markChildren = (childNode) => {
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keepIdSet.add(childNode.id);
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if (childNode.children && childNode.children.length) {
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childNode.children.forEach(markChildren);
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}
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};
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if (node.children && node.children.length) {
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node.children.forEach(markChildren);
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}
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}
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// 2. 递归遍历子节点,传递当前节点的上级链(parentNodes + 当前节点)
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if (node.children && node.children.length) {
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node.children.forEach(child => markKeepNodes(child, [...parentNodes, node]));
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}
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};
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// 遍历根节点,开始标记
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treeData.forEach(rootNode => markKeepNodes(rootNode));
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// 第二步:递归重构树形,只保留标记过的节点,保持层级
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const rebuildTree = (node) => {
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// 若当前节点无需保留,直接返回null
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if (!keepIdSet.has(node.id)) {
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return null;
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}
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// 深拷贝当前节点,避免修改原数据
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const newNode = { ...node };
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// 递归处理子节点,过滤掉无需保留的,只保留有效子节点
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if (newNode.children && newNode.children.length) {
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const newChildren = newNode.children.map(child => rebuildTree(child)).filter(Boolean);
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newNode.children = newChildren;
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} else {
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newNode.children = [];
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}
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return newNode;
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};
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// 重构根节点,过滤掉null的根节点
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const filteredTree = treeData.map(rootNode => rebuildTree(rootNode)).filter(Boolean);
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return filteredTree;
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}
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// 禁用超过当前日期的选择
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const disabledDate = (date: Date) => {
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return date > new Date() // 如果日期大于当前日期,则禁用
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